Question

A train is moving along a horizontal track. A pendulum suspended from the roof makes an angle of 4° with the vertical. Obtain the acceleration of the train. Take g= 10m/s^2

Answer 1

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We have,
$tan \theta = \frac{F_{acc}}{F_{gr}}$

=> $tan \theta = \frac{ma}{mg}$

=> $tan \theta = \frac{a}{g}$

=> $a = g× tan\theta$

Given,
Angle $\theta$= 4°
g = 10 $m/s^{2}$

Substitute g = 10 and $\theta$=4
=> $a = 10× tan 4^{0}$

The value of tan 4°= 0.069=~ 0.07

=> a = 10 × (0.07) = 0.7 $m/s^{2}$

So The Acceleration of the train is 0.7 $m/s^{2}$

Answer 2

Answer:

Explanation:

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