Question

A train is moving eastward at 10 m/sec.
A waiter is walking eastward at 1.2m/
sec; and a fly is charging toward the
north across the waiter's tray at 2 m/s.
What is the velocity of the fly relative to
Earth
​

Answer 1

Answer:

11.2m/s

Explanation:

see the picture

Answer 2

Answer:

The velocity of the fly tray relative to  earth is 11.3 m/s.

Explanation:

Given that,

Speed of train = 10 m/s eastward

Speed of waiter = 1.2 m/s east ward

Speed of tray = 2 m/s north

We need to calculate the velocity of the fly tray relative to earth

Using Pythagorean theorem

$v_{z}=\sqrt{(v_{e})^2+(v_{n})^2}$

Where, $v_{e}$= velocity in eastward

$v_{n}$= velocity in north

Put the value into the formula

$v_{z}=\sqrt{(10+1.2)^2+(2)^2}$

$v_{z}=\sqrt{(11.2)^2+(2)^2}$

$v_{z}=11.3\ m/s$

Hence, The velocity of the fly tray relative to  earth is 11.3 m/s.