Question

A train start form rest and travels uniform acceleration of 0.5m/s2 for 20s.it travel uniform velocity for another 30s,the brakes are then applied so that uniform retacetion obtain and the train comes back to rest in a further 10s .snatch the using your graph .calculate the total distance travelled by train

Answer 1

The total distance travelled is 450 metres.

Please refer the above photograph for the used process.

Attachment 1 :- It is the Graph of the given motion.

Attachment 2 :- It is the solution with the help of the graph.

Construction :- AD perpendicular to 'x' axis and BE perpendicular to 'x' axis.

KEY POINTS TO REMEMBER :-

☸️ First equation of motion :-

$v = u + at$

Where v is final velocity, u is initial velocity , a is the acceleration and t is the time.

☸️ DISTANCE = AREA UNDER GRAPH.

To find the distance from the graph, area of the geometrical figure should be found.

The area is equal to the distance travelled within that span.

☸️ Area of some geometrical figures :-

$triangle = \frac{1}{2} \times base \times height \\ \\ square = {side}^{2} \\ \\ rectangle = length \times breadth \\ \\ parallelogram = base \times altitude \\ \\ rhombus = \frac{1}{2} \times d1 \times d2$

Thanks!