Question

A train travels at a certain average speed for a distanse of 54km and then travels a distance of 63km at an average speed of 6km more than the first speed.if it takes 3hours to complete the total journey.what is its first speed

Answer 1

Distance = 54 km
Let the average speed be x
Distance= 63km
The average speed to cover this distance = x+6
Total Time Taken= 3 hr.
D/S =t
therefore, 54/x + 63/x+6 = 3
54(x+6) +63x =3x(x+6)
3x^2 - 99x - 324=0
x=36, -3
Hence x= 36km/hr

Answer 2

Answer:

x= 36km/hr

Step-by-step explanation:

Distance = 54 km

Let the average speed be x

Distance= 63km

The average speed to cover this distance = x+6

Total Time Taken= 3 hr.

D/S =t

therefore, 54/x + 63/x+6 = 3

54(x+6) +63x =3x(x+6)

3x^2 - 99x - 324=0

x=36, -3

Hence x= 36km/hr