xy=20, where x y are consecutive numbers. Find x,y
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2
hi friend,
let x,x+1 be the consecutive numbers
now ,x(x+1)=20
→x²+x=20
→x²+x-20=0
→x²+5x-4x-20=0
→x(x+5)-4(x+5)=0
→(x-4)(x+5)=0
so x= 4,-5
so required numbers are 4,5 and -5,-4
I hope this will help u ;)
let x,x+1 be the consecutive numbers
now ,x(x+1)=20
→x²+x=20
→x²+x-20=0
→x²+5x-4x-20=0
→x(x+5)-4(x+5)=0
→(x-4)(x+5)=0
so x= 4,-5
so required numbers are 4,5 and -5,-4
I hope this will help u ;)
Answered by
2
Hai friend,
here is your answer.
Here x*y =20
let x be n
then y will be( n+1)
n(n+1)=20
n²+n-20=0
n²+5n-4n-20=0
n(n+5)-4(n+5)=0
(n-4)(n+5)=0
n=4 or -5
x=n=4,-5
y =n+1 =5,-4
So (x,y) = (4,5), (-5,-4)
hope helped!
here is your answer.
Here x*y =20
let x be n
then y will be( n+1)
n(n+1)=20
n²+n-20=0
n²+5n-4n-20=0
n(n+5)-4(n+5)=0
(n-4)(n+5)=0
n=4 or -5
x=n=4,-5
y =n+1 =5,-4
So (x,y) = (4,5), (-5,-4)
hope helped!
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