Math, asked by sivanandanam2007, 11 months ago

a two digit number is such that the product of its digits is 18 when 63 is subtracted from the number the digits interchange their places find the number

Answers

Answered by StingRaider
2

hello there!!!

let the two digit number be 10x+ y

ATQ,. x × y= 18..........(1)

10x + y - 63 = 10 y + x

9x - 9y - 63= 0

9x - 9y = 63

x-y = 7..........(.2)

x= 7+y

put value of x in eq 1b, we get

( 7+y ). y = 18

y² + 7y = 18

y² +7y-18=0

y² +9y -2y -18= 0

y(y+9) -2 ( y +9) =0

( y+9) (y-2). = 0

y=-9 , y = 2

y= 2........

so, x= 7+2=9

therefore the two digit number is 10(9)+2

= 92.....

HOPE IT HELPS YOU

Answered by KJB811217
1

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