A u-tube of uniform cross section (see fig.) is partially filled with a liquid i. Another liquid ii which does not mix with liquid i is poured into one side. It is found that the liquid levels of the two sides of the tube are the same, while the level of liquid i has risen by 2cm. If the specific gravity of liquid i is 1.1, the specific gravity of liquid ii must be
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It is clear that the height of liquid column I in right limb is (h+2) cm and the height of liquid column II in left limb is 2.0 cm and of liquid column I is h cm.
\therefore 2 \times \rho_2 \times g + h \times 1.1 \times g=(2+h) \times 1.1 \times g \\\Rightarrow 2 \rho_2 = 2.2 \\\Rightarrow \rho_2 = 1.1∴2×ρ
2
×g+h×1.1×g=(2+h)×1.1×g
⇒2ρ
2
=2.2
⇒ρ
2
=1.1
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