Question

A vernier callipers used by student has 20 divisions in 1cm on main scale. 10 vernier divisions coincide with 9 main scale divisions. When jaws are closed, zero of main scale is on left of zero of vernier scale and 6th divisions of vernier scale coincides with any mains scale divisions. He placed a wooden cylinder in between the jaws and measure the length. The zero of vernier scale is on right of 3.2 cm mark of main division and 8th division of vernier scale with any main scale division. When he measures diameter of cylinder he finds that zero of vernier scale lies on right of 1.5 cm mark of main scale and 6th division of vernier scale coincides with any main scale division. Least count and zero error of vernier callipers are

Answer 1

I hope that you got your required answer.
Please mark my answer brainliest.

Answer 2

Explanation:

Length of one main scale division 1

$msd = \frac{1}{20} = 0.05cm$

Since, 20th division of vernier scale coincides with 17th division of main scale.

Least count of vernier callipers, L.C.=1 M.S.D.

$- \frac{ 17}{20} \times m.s.d \: \\ = > L.C.=0.5 \ - \frac{ 17}{20} \times 0.5 = 0.75$

Correct answe-r is option D.