Physics, asked by NairaRajpal, 1 year ago

A wave pulse of frequency 200Hz,ona string moves a distance 8min 0.05 s.Calculate:(a) the velocity of pulse (b) the wavelength of wave on string.

Answers

Answered by athishvaishu123
31

Answer:

80

Explanation:

v=8/0.05=160 m/s

W=V/F

160/200

=0.8=80

Answered by Anonymous
5

Given:

  • The frequency of wave pulse = 200 Hz
  • Distance = 8 m
  • Time = 0.05 s

To Find:

  • (a) the velocity of the pulse
  • (b) the wavelength of the wave of the string.

Solution:

(a) Finding the velocity.

The formula to find the velocity of the pulse is given by,

v = s/t → {equation 1}

Where "s" is the distance, "t" is the time.

On substituting the given values in equation 1 we get,

⇒ v = 8/0.05  { dividing the terms }

⇒ v = 160 m/s

(b) Finding the wavelength of the pulse.

The formula to find the wavelength is given by,

λ = v/f → {equation 2}

Where "λ" is the wavelength,  "v" is the velocity, and "f" is the frequency.

On substituting the given values in equation 2 we get,

⇒ λ = 160/200

⇒ λ = 0.8 m

∴ (a) The velocity of the pulse = 160 m/s and (b) the wavelength of the pulse = 0.8 m

Similar questions