A wave pulse of frequency 200Hz,ona string moves a distance 8min 0.05 s.Calculate:(a) the velocity of pulse (b) the wavelength of wave on string.
Answers
Answered by
31
Answer:
80
Explanation:
v=8/0.05=160 m/s
W=V/F
160/200
=0.8=80
Answered by
5
Given:
- The frequency of wave pulse = 200 Hz
- Distance = 8 m
- Time = 0.05 s
To Find:
- (a) the velocity of the pulse
- (b) the wavelength of the wave of the string.
Solution:
(a) Finding the velocity.
The formula to find the velocity of the pulse is given by,
v = s/t → {equation 1}
Where "s" is the distance, "t" is the time.
On substituting the given values in equation 1 we get,
⇒ v = 8/0.05 { dividing the terms }
⇒ v = 160 m/s
(b) Finding the wavelength of the pulse.
The formula to find the wavelength is given by,
λ = v/f → {equation 2}
Where "λ" is the wavelength, "v" is the velocity, and "f" is the frequency.
On substituting the given values in equation 2 we get,
⇒ λ = 160/200
⇒ λ = 0.8 m
∴ (a) The velocity of the pulse = 160 m/s and (b) the wavelength of the pulse = 0.8 m
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