a² + b² + 2ab, 3a² - 2ab + 5b² Subtract the given expressions.
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Answered by
2
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HERE IS UR ANS
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a2 + b2+2ab
3a2+5b2-2ab
[a2+b2+2ab]3
[3a2+5b2-2ab]1
3a2+3b2+6ab
3a2+5b2-2ab
- - +
___________
-2b2+8ab
____________
《-2b2 +8ab》is the ans
HOPE IT HELPS U DEAR ^_^_
HERE IS UR ANS
________________^_^
a2 + b2+2ab
3a2+5b2-2ab
[a2+b2+2ab]3
[3a2+5b2-2ab]1
3a2+3b2+6ab
3a2+5b2-2ab
- - +
___________
-2b2+8ab
____________
《-2b2 +8ab》is the ans
HOPE IT HELPS U DEAR ^_^_
Answered by
0
Answer:
Given first expression a²+b²+2ab,
Second expression = 3a²-2ab +5b²
i ) Subtract first expression from
Second expression, we get
3a²-2ab+5b²-( a²+2ab+b² )
= 3a²-2ab+5b²-a²-2ab-b²
= 2a² - 4ab + 4b²
ii ) Subtract second expression
from first expression , we get
a² + 2ab + b² - ( 3a² - 2ab + 5b² )
= a² + 2ab + b² - 3a² + 2ab - 5b²
= -2a² + 4ab - 4b²
••••
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