ABC is a triangle and D is midpoint of BC.The perpendicular to D to AB and AC are equal.Prove that the triangle is isosceles.
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Answer
Proof -
In ∆ ADB and ∆ ADC
AB= AC.. Given
AD= AD common side
Angle ADC = Angle ADB.. Each 90°
Hence they are congruent.
so, Angle B= Angle C.. cpct
hence its isosceles triangle
Answer
Proof -
In ∆ ADB and ∆ ADC
AB= AC.. Given
AD= AD common side
Angle ADC = Angle ADB.. Each 90°
Hence they are congruent.
so, Angle B= Angle C.. cpct
hence its isosceles triangle
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