Question

∆ABC- ∆PQR, AB/PQ- 5/4 BC=10then find QR​

Answer 1

Answer:

In ΔABC and ΔPQR

AB=PQ

And BC=QR

CB And RQ extended to X and Y

∠ABX=∠PQY

∠ABC=180° −∠ABX=180 °∠PQY

∠PQR=180°−∠PQY=∠ABC

We get in both triangles

AB=PQ

BC=QR

And ∠ABC=∠PQR

Then both triangle are congruent

i.e. ΔABC=ΔPQR