ABCD is a parallelogram in which DL perpendicular to AB and BM perpendicular to AD such that AD is equal to 6 CM CM is equal to 10 cm and DL is equal to 8 cm find AB
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area of parallelogram= base × altitude
for ABCD
AE is perendicular to DC
AREA OF PARALLELOGRAM
DC×AE
AB× AE
18× 16=equation 1
for ABCD
CE is perpendicular to AD
AREA OF PARALLELOGRAM
AD× CF
AD× 10= equation 2
from equation 1 and 2
16×18=AD×10
AD=16×18÷10 =12·8CM
therefore AD =12.8cm
for ABCD
AE is perendicular to DC
AREA OF PARALLELOGRAM
DC×AE
AB× AE
18× 16=equation 1
for ABCD
CE is perpendicular to AD
AREA OF PARALLELOGRAM
AD× CF
AD× 10= equation 2
from equation 1 and 2
16×18=AD×10
AD=16×18÷10 =12·8CM
therefore AD =12.8cm
sanatw1404:
AD is given AB ko find krna hai
toh AB 18 H
AB IS 18 cm
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