ABCD is a parallelogram such that ∠BAD = 120o
and AC bisects ∠BAD show that ABCD is a
rhombus.
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Answer:
1) draw diagram
as it is parallelogram , the angle opposite to <BAD is 120 degrees
to prove: a rhombus has all sides equal
so,
we know that ac bisects <BAD
so <DAC = <CAB = 60 degrees
similarly <BCA and <DCA are 60 degrees
we can see that <CAB and <BCA are = to 60 degrees
so we can conclude that AB = BC
and BC = AD (opp sides of parallelogram are equal)
so we can conclude that AB=BC=CD=AD
thus ABCD is a rhombus.
Hence, proved
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