Question

ABCD is a rectangle. The perpendicular DN from D on AC divides angle D in the ratio 2:3. Find angle NDB​

Answer 1

Given:

The perpendicular DN from D on AC divides angle D in the ratio 2:3.

To find:

angle NDB​.

Solution:

1) We all know the at the diagonal of the rectangle bisects the angle of the rectangle. So the ∠BDA = 45°.

2) It is known to everyone that the angle of the rectangle is 90° and the angle D is divided into 2:3 but the total of the angle must be 90°.

3) for the ∠D

• 2x + 3x = 90°

• 5x = 18°

• so ∠ADN = 2x = 36°

4) ∠NDM = ∠BAD - ∠ADN

               = 45° - 36°

               = 9°

angle NDB is 9°

Answer 2

Answer:

Step-by-stABCD is a rectangle. The perpendicular DN from D on AC divides D in the ratio 2:3

Find NDB.

ep explanation: