Math, asked by nkbc, 1 year ago

ABCD is a rhombus of perimeter 16 CM. if it's one side AB and a diagonal AC are (3x+1)cm each then find x, and angle ADC and angle DAB

Answers

Answered by Rishab143
26
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Answered by amitnrw
23

x = 1 , ∠BAC = 60° , ∠DAB = 120°

Step-by-step explanation:

ABCD is a rhombus of perimeter 16 CM

=> AB = BC = CD =  AD = 16/4 = 4 cm

AB = 3x + 1

=> 3x + 1 = 4

=> x = 1

AD = CD= AC = 4 cm

Hence ΔADC Equilateral triangle

=> ∠D = ∠ADC = 60°

∠DAC = 60°

Similarly AB = BC = AC = 4 cm

Hence ΔABC Equilateral triangle

=> ∠BAC = 60°

∠DAB = ∠DAC + ∠BAC

=> ∠DAB = 60° + 60°

=> ∠DAB = 120°

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