ABCD is a rhombus whose diagonals intersect at O show that triangle ABC is congruent to triangle COD
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given:abcd is a rhombus.
a rhombus is a parallelogram
therefore ab=cd and bc=ad
also given that diagonals are bisecting each other at O
thereforeOA=OC and OB=OD.
prove: ABC congruent to COD
PROOF:
IN triangle ABC and triangle COD
AB=CD(given)
ANGLE. BAO= ANGLE. DCO (A.I.A)
ANGLE. ABO= ANGLE. CDO (A.I.A)
Therefore, ABC is congruent to COD
proved.
a rhombus is a parallelogram
therefore ab=cd and bc=ad
also given that diagonals are bisecting each other at O
thereforeOA=OC and OB=OD.
prove: ABC congruent to COD
PROOF:
IN triangle ABC and triangle COD
AB=CD(given)
ANGLE. BAO= ANGLE. DCO (A.I.A)
ANGLE. ABO= ANGLE. CDO (A.I.A)
Therefore, ABC is congruent to COD
proved.
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