The acceleration due to gravity near the earth's surface is 9.8m/s2 and the earth's radius is 6400km. From this data calculate the mass of the Earth. Use any universal constant if required.
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Answered by
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Since g = G*Me/ Re^2
=) 9.8m/s^2 = 6.67*10^-11 Nm^2 /kg^2 * Me / (6400*1000m)^2
=) 9.8m/s^2 = 6.67*10^-11 Nm^2 /kg^2 * Me /(6.4*10^6 m) ^2
=) 9.8m/s^2 = 6.67*10^-11 Nm^2 /kg^2 * Me / 40.96*10^12 m^2
=) 9.8 * 40.96 * 10^12 / 6.67*10^-11 = Me
=) 9.8*40.96/6.67 * 10^(12+11) = Me
=) 60.18 * 10^23 = Me
=) 6 * 10^24 kg
Hope it's helpful to u.
=) 9.8m/s^2 = 6.67*10^-11 Nm^2 /kg^2 * Me / (6400*1000m)^2
=) 9.8m/s^2 = 6.67*10^-11 Nm^2 /kg^2 * Me /(6.4*10^6 m) ^2
=) 9.8m/s^2 = 6.67*10^-11 Nm^2 /kg^2 * Me / 40.96*10^12 m^2
=) 9.8 * 40.96 * 10^12 / 6.67*10^-11 = Me
=) 9.8*40.96/6.67 * 10^(12+11) = Me
=) 60.18 * 10^23 = Me
=) 6 * 10^24 kg
Hope it's helpful to u.
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14
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