Question

ABCD is a square of side a .A body starts from A and reaches at c along side AB an BC .the ratio of displacement to the distance covered is ?​

Answer 1

Answer:

☆root2a

Explanation:

SO AB length is a and BC length is a.

Body is moving in AC which is diagonal of square.

now it forms right angle triangle.

apply pythagorous theorem.

ACSQUARE=ABSQUARE +BCSQUARE.

x^2=a^2+a^2

x=root2a

Answer 2

Answer: 1:√2

Explanation: Let the side be x

Distance covered = AB+BC= 2x

Displacement = x√2

Ratio = x√2:2x

          = √2:2 = 1:√2

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