prove that (2^30 + 2^29 + 2^28) / (2^31 + 2^30 - 2^29) = 7/10
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(2^30 + 2^29 + 2^28) / (2^31 + 2^30 - 2^29)
= 2^28[2^2 + 2^1 + 1] / 2^29[2^2 + 2^1 - 1] =2^28[7] / 2^29[5]
= 7/(2×5)
= 7/10, hence proved
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dhruv0002:
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