Question

According to the following equation, how many moles of CO2 can be produced from 10.0 g Fe2O3 and excess CO?

3 Fe2O3 + CO → 2Fe3O4 + CO2

IS IT
a- 3.33 moles
b- 0.0209 moles
c- 0.918 moles
d- 0.357 moles

Answer 1

$\huge\purple{As-Salamu-Alykum}$

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$\huge\red\bold{Balanced Equation : }$

3Fe2O3 + CO >>2Fe3O4 + CO2

From this balanced equation it is clear that :-

3 moles of Fe2O3 are produced from 1 mole CO2

So.....

10g of Fe2O3 are given , therefore number of moles of Fe2O3 are :-

Moles of Fe2O3 =mass/molar mass

Moles of Fe2O3 =10/160

Moles of Fe2O3 =0.06 mol

Now ...

As 3 mole Fe2O3 = 1 mole CO2

So ....

0.06 mole Fe2O3 = 1 × 0.06 ÷3 Fe2O3

$\huge\red\bold{0.06 mole Fe2O3 = 0.02 mole CO2 }$


$\huge\red\bold{Option 2 is correct }$

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$\huge\purple{INSHALLAH it will help U}$