Question

HEY GUYS...!!!⚡️✌️✌️

HOW ARE YOU...??❣️❣️

I HAVE A QUESTION FOR YOU,WILL YOU PLEASE HELP ME IN THIS....??♥️♥️

BEST EXPLANATION WILL BE BRAINLIEST ONE...✌️✌️♥️

Answer 1

Hello dear!! Here is yout answer!!
See the attachment.... Hope it helps uhh!!!

Answer 2

Answer:

tan²A

Step-by-step explanation:

(i)

$Given:\frac{1+tan^2A}{1+cot^2A}$

$=\frac{sec^2A}{cosec^2A}$

$=\frac{1}{cos^2A}*\frac{sin^2A}{1}$

$=\frac{sin^2A}{cos^2A}$

$=tan^2A$

(ii)

$Given:(\frac{1-tanA}{1-cotA})^2$

$=(\frac{1-tanA}{1-\frac{1}{tanA}})^2$

$=(\frac{1-tanA}{\frac{tanA-1}{tanA}})^2$

$=-(\frac{1-tanA}{\frac{1-tanA}{tanA}})^2$

$=(-tanA)^2$

$= tan^2A$

∴ (1) & (ii) = tan²A.

Hope it helps!