Question

aman's income is 20% less than that of anil . how much percent is anil's income more than aman's income ?​

Answer 1

$\huge\mathfrak{Answer}$

Let Anil's income is =x

then Aman's income will be

= x - ((x*20)/100)

=8x/10

anil's income more than aman's is

=x-(8x/10)

=2x/10

Now percentage of anil's income which is more than aman's is

=(2x/10)/(8x/10)* 100

=(1/4)*100

=25%

Answer 2

Answer:

120%

Step-by-step explanation:

Let anil's income be ₹100, then aman's income will be 20% less than that of anil i.e.

₹100-(20% of ₹100) which is equal to ₹80.

Let anil's income be x% more than that of aman. So, x% of ₹80=₹100

(x/100)×80=100

So, x comes out to be 120%