Question

An electric pump is 60% efficient and is rated at 2HP. Calculate the maximum amount of water it can lift through a height of 5m in 40s (take g 10ms and 1HP= 750W

Answer 1

Hi.

Here is the answer---

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Let the amonit of water be m kg.

Given Comditions-

Power = 2 HP.
= 2 × 750
= 1500 W. As per as the question, electric pump is 60% efficient. Thus, Power of the pump = (60/100) × 1500. = 900 W.
Height = 5 m
Time = 10 seconds.
Acceleration due to gravity = 10 m/s^2

Using the formula,
Work done = mgh
= m × 10 × 5
= 50 × m.

Now, Power = Work/Time
900 = 50 × m/10
m = 180 kg.

Thus, the amount of water is 180 kg.

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Hope it helps.

Have a Nice day.