Question

An electric pump on the ground floor of a building takeS 10 minutes to fill a tank of volume 30m^3with water if the tank is 60m above the ground and the efficiency of the pump is 30℅ how much electric power is consumed by the pump in filling the tank

Answer 1

Answer:

Energy required=mgh

=30×10×60=18000J

power = energy/time

= 18000/60×10

= 30watt

Efficiency is 30%

so let power consumed by motor be x

x×30/100=30

x=3000/30

x= 100W

Electric power consumed by machine is 100w.

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Answer 2

Explanation:

Energy=mgh. (mass=density*volume)

=30*1000*10*60=18000000 J

efficiency=work output/work input

input=18000000*100/30=60000000J

power=input/time in sec

power=60000000/600=100000

power( consumed) =100kW.