Question

Find remainder when 7^3 + 8^3+9^3+10^3 is divided by 34. ​

Answer 1

Step-by-step explanation:

7^3+8^3+9^3+10^3 DIVIDED BY 34

7³=343

8³=512

9³=729

10³=1,000

SO GIVEN

SUM ALL EQUATION IS

343+512+729+1,000=2584

2584/34 = 76

PLEASE MARK AS BRAINLIST

THE REMAINDER IS 0

Answer 2

Question :-

• Find remainder when 7^3 + 8^3+9^3+10^3 is divided by 34. 

Solution :-

Lets Try to Solve with a Tricky way :-

→ 7³ + 8³ + 9³ + 10³

→ 7³ + (7+1)³ + (7+2)³ + (7+3)³

→ 7³ + (7³ + 1³ + 3*7*8) + (7³ + 2³ + 3*7*2*9) + (7³ + 3³ + 3*3*7*10) { using (a + b)³ = a³ + b³ + 3ab(a+b) } .

→ 7³*4 + 1 + 2³ + 3³ + 3*7*8 + 6*7*9 + 9*7*10

→ 1372 + 1 + 8 + 27 + 168 + 378 + 630

→ 2584

Now, Dividing The sum by 34 , we get ,

→ 2584 = 34 * 76 + 0

Hence, The Remainder will be 0 .