An integer is chosen from 1 to 50. Find the probability that it is multiple of 5 or multiple of 7.
Answers
Answered by
6
Final Answer : 8/25
Steps:
1) An integer is chosen from 1 to 50:
= > Total no. of outcomes, n(S) = 50
2) Numbers which are multiple of 5 :
5,10,....50 : 10 terms
Numbers which are multiple of 7 :
7 , 14 ..... 49 : 7 terms.
3) LCM : (7,5) = 35
35 is common in both multiples :
Hence, Total no. of Favourable terms ,n(E) : 10+7-1=16
Therefore, Probability of getting number which is multiple of 7 and 5 :
n(E)/n(S) = 16/50 = 8/25 .
Steps:
1) An integer is chosen from 1 to 50:
= > Total no. of outcomes, n(S) = 50
2) Numbers which are multiple of 5 :
5,10,....50 : 10 terms
Numbers which are multiple of 7 :
7 , 14 ..... 49 : 7 terms.
3) LCM : (7,5) = 35
35 is common in both multiples :
Hence, Total no. of Favourable terms ,n(E) : 10+7-1=16
Therefore, Probability of getting number which is multiple of 7 and 5 :
n(E)/n(S) = 16/50 = 8/25 .
Answered by
1
Answer:
Final Answer: 8/25
Steps:
1) An integer is chosen from 1 to 50: = > Total no. of outcomes, n(S) = 50
2) Numbers which are multiple of 5: 5,10,....50 : 10 terms
Numbers which are multiple of 7: 7,14 .. 49 : 7 terms.
3) LCM: (7,5) = 35 35 is common in both multiples :
Hence, Total no. of Favourable terms ,n(E) : 10+7-1=16
Therefore, Probability of getting number which is multiple of 7 and 5:
n(E)/n(S) = 16/50 = 8/25.
Similar questions