Question

An object dropped from a cliff falls with a constant acceleration of 10 m/s2. Find its speed 5 s after it was dropped.​

Answer 1

Initial velocity = 0ms-1.

Acceleration = 10ms-2. (a)

Time = 5s (t)

Final velocity(v) = ?

Using the formula v = u + at we get:

v = (0 + 10×5)ms-1.

v = (0 + 50)ms-1

Therefore v = 50ms-1

Answer 2

Given : A = 10 m / s²

Time = 5s

Initial velocity = 0 m / s [ Initially the object is at rest ]

Speed (v) = ???

Here we can use equation of motion

=> v = u + at

v = 0 + 10 (5)

v = 50 m / s


So speed = 50 m / s



HOPE IT HELPS U.