Question

An object is dropped from rest at a height of150m and simultaneously another object is dropped from rest at a height of 100m. What is their heights after 2s if both the objects drop with same acceleration? How does the difference in heights vary with time

Answer 1

Let first object be A.
Let second object be B.
Object A Object B
U=0. U=0.
S=150m. S=100m.
T=2s. T=2s.
S=ut+1/2at2
150=0×2+1/2a×(2)2
150=0+1/2a×4
150=2a
150/2=a
75m/s2=a
As acceleration of both objects is same so acceleration of object B is also 75m/s2.