An object of mass 16 kg its moving with an acceleration of 3m/s calculate the applied force if the same force is applied on an object of mass 24 kg how much will be the acceleration
Answers
Answered by
60
Heya dear
We know that F = ma
case 1st when force is applied on 16kg block
moving with acc. 3m/s²
so use F= ma
plug the values of a and m
F = 16×3 => 48N
now same force is applied on body of mass 24 Kg
so
again plug the values in the formula
we get
48 = 24 × a'
so a' = 2 m/s² { note it will be retardation since the force is opposing the motion.
We know that F = ma
case 1st when force is applied on 16kg block
moving with acc. 3m/s²
so use F= ma
plug the values of a and m
F = 16×3 => 48N
now same force is applied on body of mass 24 Kg
so
again plug the values in the formula
we get
48 = 24 × a'
so a' = 2 m/s² { note it will be retardation since the force is opposing the motion.
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Answered by
70
By Newton's second law of motion,
F = ma
We have , m = 16 kg and a = 3 m/s^2
Just plug in the values
F = 16 x 3 = 48 N
Now, it's given that the same force is applied on m = 24 kg.
Again, F = ma
48 = 24a
a = 2 m/s^2
Hence, required answer is F = 48 N , a = 2 m/s^2
Hope This Helps You!
F = ma
We have , m = 16 kg and a = 3 m/s^2
Just plug in the values
F = 16 x 3 = 48 N
Now, it's given that the same force is applied on m = 24 kg.
Again, F = ma
48 = 24a
a = 2 m/s^2
Hence, required answer is F = 48 N , a = 2 m/s^2
Hope This Helps You!
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