Question

answer please it's very urgent​

Answer 1

Answer:

15 V

Explanation:

Current flowing through 9 Ω resistor:

$I^2_1$ = 36/9 = 4 A

$I$ = 2 A

Resistors 9 Ω and 6 Ω will have the same potential difference since they are connected in parallel.

$9I_1=6I_2$

We have:

$I_1$ = 2A

So:

$I_2$ = (9 × 2)/6 = 3 A

Net current:

$I_1+I_2$ = 2A + 3A = 5 A

Potential difference across 3 Ω resistor:

V = IR

V = 5 × 3

∴ V = 15 V