answer this for the 14th question
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Proof:
Step-by-step explanation
In Triangle ABD
AB+BC>AC(sum of two sides of a triangle is greater than the third side){eq.1}
In Triangle BCD
CD+DA>DB(sum of two sides of a triangle is greater than the third side){eq.2}
Eq.1+Eq.2=
AB+BC+CD+DA>DB+AC
Hence Proved.
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