answer this question plssss
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RishabhSood:
16 or 17?
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Answered by
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x^2+4x-3x-12
=x(x+4)-3 (x+4)
=(x-3)(x+4)
therefore zeroes are 3 and -4
verification
let a =3 and b =-4
so a+b=- coeff of x/coeff of x^2
=-1=-1
and ab=constant term/coefficient of x^2
=-12=-12
lhs=rhs
hence verified
=x(x+4)-3 (x+4)
=(x-3)(x+4)
therefore zeroes are 3 and -4
verification
let a =3 and b =-4
so a+b=- coeff of x/coeff of x^2
=-1=-1
and ab=constant term/coefficient of x^2
=-12=-12
lhs=rhs
hence verified
Answered by
0
x^2+4x-3x-12
=x(x+4)-3 (x+4)
=(x-3)(x+4)
therefore zeroes are 3 and -4
verification
let a =3 and b =-4
so a+b=- coeff of x/coeff of x^2
=-1=-1
and ab=constant term/coefficient of x^2
=-12=-12
lhs=rhs
hence verified
May this help you alot..
=x(x+4)-3 (x+4)
=(x-3)(x+4)
therefore zeroes are 3 and -4
verification
let a =3 and b =-4
so a+b=- coeff of x/coeff of x^2
=-1=-1
and ab=constant term/coefficient of x^2
=-12=-12
lhs=rhs
hence verified
May this help you alot..
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