anu is four years older than sunil. Eight years ago Anu was three times sunils age. find the age of sunil and anu
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Answer:
Let the present ages of Anu and Sunil be x and y respectively-
According to question-
x=y+4 (Equation 1)
Eight years ago,ages of anu sunil would be (x-8) and (y-8) respectively-
Now,according to the question-
x-8=3(y-8) (Equation 2)
On solving equation 1 and 2,we get -
x=14,y=10.
raazJet:
can you please explin it
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Solutions :-
Let the age of Sunil be x
Anu's age = x + 4
8 years ago, Anu was 3 times Sunil's age.
A/q
⇒(x+4) - 8 = 3(x-8)
⇒ x - 4 = 3x - 24
⇒ x - 3x = -24 + 4
⇒ -2x = -20
⇒ x = -20/-2 = 10
Hence,
Age of Sunil = x = 10 years
Age of Anu = x + 4 = (10 + 4) years = 14 years
_______________________
✯ @shivamsinghamrajput ✯
Let the age of Sunil be x
Anu's age = x + 4
8 years ago, Anu was 3 times Sunil's age.
A/q
⇒(x+4) - 8 = 3(x-8)
⇒ x - 4 = 3x - 24
⇒ x - 3x = -24 + 4
⇒ -2x = -20
⇒ x = -20/-2 = 10
Hence,
Age of Sunil = x = 10 years
Age of Anu = x + 4 = (10 + 4) years = 14 years
_______________________
✯ @shivamsinghamrajput ✯
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