Question

Anwar save some amount every month in first three months he said 200 rupees 250 rupees and 3 300 rupees respectively in which month will is saved thousand rupees​

Answer 1

Answer:

17th year

Step-by-step explanation:

ap→

200,250,300,..........., 1000

here

a=200

an=1000

d=50

n=?

an=a+(n-1)d

1000=200+(n-1)50

1000=200+50n-50

1000=200-50+50n

1000=150+50n

50n=1000-150

50n=850

n=850/50

n=17

Answer 2

Answer:

he saved ₹1000 in 17th month

Step-by-step explanation:

a=200

d=250-200=50

1000=a+(n-1)d

1000=200+(n-1)50

1000-200=(n-1)50

800/50=n-1

16=n-1

16+1=n

n=17