Question

In the given figure, DEFG is a square and angle BAC = 90 . show that FG2 = BG * FG
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Answer 1

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Answer 2

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Step-by-step explanation:

ΔADE ~ ΔFEC ................ (1)

ΔADE~ ΔFEC  ................ (2)

from (1) and (2) ΔGBD ~ ΔFEC

∴ $\frac{GB}{FE}$ = $\frac{GD}{FC}$

⇒ GD × FE = BG × FC

⇒ FG² = BG × FC   (∵ BG = FC = FG)

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