ARB represent a semicircular plate where AB=14 cm.A semicircle ASO is cut away.( o is the mid point of AB). what is the area of the remaining portion?(Takeπ=22/7).
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ARB is a semicircle with a diameter of 14 cm.
ASO is a semicircle with a diameter of 7cm since it cuts AB at the center...
If ASO is cut from ARB then the remaining area is area of ARB-area of ASO.
Area of ARB=22/7×7×7=154cm2
Area of ASO=22/7×3.5×3.5=38.5cm2.
The remaining area :154-38.5=115.5cm2
ASO is a semicircle with a diameter of 7cm since it cuts AB at the center...
If ASO is cut from ARB then the remaining area is area of ARB-area of ASO.
Area of ARB=22/7×7×7=154cm2
Area of ASO=22/7×3.5×3.5=38.5cm2.
The remaining area :154-38.5=115.5cm2
faizal5:
thnx
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