Math, asked by jvardhman69p9a02p, 1 year ago

Aryabhatta formulas....

Answers

Answered by ratnamsarika123
2


He gave the formula (a + b)2 = a2 + b2 + 2ab

He taught the method of solving the following problems as shown above

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Answered by Anonymous
0

Step-by-step explanation:

Ø formula: Aryabhatta gives formulae for the areas of a triangle, square, rectangle, rhombus, circle etc. sin (n+1)x - sin nx in terms of sin nx and sin (n-1) x.

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