Ask your question hereA car accelerates from rest at a constant rate a for sometime,after which it decelerates at a contant rate b to come to rest.if the total time lapsed is t.calculate the max velocity reached and d total distance travelled?
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s1 = 1/2 * a * t1 ² v1 = a * t1 --- eq 1
s2 = v1 ² / 2 b v1 = b * (t - t1) -- eq 2
from eq 1 and 2, t1 = b t / (a+b)
max velocty reached : a * b t / (a+b)
d = s1+s2 = v1² / 2a + v1² / 2b = a b t² / 2(a+b)
s2 = v1 ² / 2 b v1 = b * (t - t1) -- eq 2
from eq 1 and 2, t1 = b t / (a+b)
max velocty reached : a * b t / (a+b)
d = s1+s2 = v1² / 2a + v1² / 2b = a b t² / 2(a+b)
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