Question

b) Divide 9x - 6x2 + x3 – 2 by (x + 2)​

Answer 1

Answer:

x-2)x³-6x²+9x-2(x²-4x+1

-(x³-2x²)

___________

-4x²+9x-2

-(-4x²+8x)

_______________

x-2

-(x-2)

______________

0

_______________

quotient = q(x)=x²-4x+1

remainder =r(x)=0

divisor =g(x)=x-2

dividend =g(x)×q(x)+r(x)

x³-6x²+9x-2=(x-2)(x²-4x+1)+0

x³-6x²+9x-2=x³-6x²+9x-2

Answer 2

Answer:;

$7 \times - 6 \times 2 + \times 3 - 4$

this is a answer I hope this is a correct answer ok