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THEREFORE the value of x is 8
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i) Total no. of balls = 18
no, of red balls = x
hence, P(Red) = x/18
P(not Red) = 1-x/18 = (18-x)/18
ii) If 2 more red balls are put,
Then Total No. of balls = 20
no. of red balls = (x+2)
Hence, P'(Red) = (x+2)/20
But , P'(Red) = 9*P(Red)/8
Hence, (x+2)/20 = 9*x/8*18
hence, x = 8
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