Question

By elimination method 5x+7y+2=0 and 4x+6y+3=0

Answer 1

Answer:

we need to find the value of x and y in both the equation.

5x+7y+2=0   .............(1)

4x+6y+3=0   .............(2)

by elimination method,

5x+7y+2=0

5x= -2-7y

x=(-2-7y)/5 ......................(3)

we got the value of x from equation(1)

now put the value of x obtained from eqn (1) in eqn(2)

4x+6y+3=0

[4(-2-7y)]/5 +6y+3=0

[-8-28y]/5 +6y= -3

{-8-28y+30y}/5 = -3

{-8+2y}=-3 * 5

-8+2y = -15

2y= -15+8

2y= -7

y=-7/2= -3.5

now put the value ofy in eqn(3)

x=(-2-7y)/5

x=(-2-7 * 7)/2 * 5

x=(-2-49)/10

x(-51)/10=-5.1

hence, x = -5.1        y= -3.5

Step-by-step explanation: