by how much 4 x^2 minus 7xy exceeds the sum of 5 x^2 + 4xy and -3x^2 + 2xy?
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5x²+4xy
-3x²+2xy
=2x²+6xy
4x²-7xy
2x²+6xy
=2x²-13xy
-3x²+2xy
=2x²+6xy
4x²-7xy
2x²+6xy
=2x²-13xy
rakshat80:
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Answered by
1
Answer:
2x² - 13xy
Step-by-step explanation:
Given in the attached picture.
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