Calculate delta G°and log K^c for Cd+(aq) + Zn (s) = Zn2+(aq) + Cd(s) given E° Cd2+/Cd = - 0.403 V and E° Zn2+/Zn = - 0.763V
Answers
Answered by
14
Cd2+(aq) + Zn(s) → Zn2+(aq) + Cd(s)
if E°
Cd2+/Cd = – 0.403 V.
E°
zn2+/zn = – 0.763 V
harshitagarwal624:
hi
Similar questions