Chemistry, asked by mehulisarkarliza, 1 year ago

Calculate delta G°and log K^c for Cd+(aq) + Zn (s) = Zn2+(aq) + Cd(s) given E° Cd2+/Cd = - 0.403 V and E° Zn2+/Zn = - 0.763V

Answers

Answered by shifa2171
14

Cd2+(aq) + Zn(s) → Zn2+(aq) + Cd(s)

if E°

Cd2+/Cd = – 0.403 V.

zn2+/zn = – 0.763 V


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