Question

calculate % of oxygen in glucose​

Answer 1

Answer:

glucose, so the mass of oxygen in 1 mole of glucose = 6 × 16.00 g = 96.00 g. % oxygen = 96.00 × 100 % = 53.3 % by mass.

Answer 2

Answer:

53.3% of oxygen is present in glucose

Explanation:

O*6=16*6=96

O*6=16*6=96Calculate molecular weight 6*C+12*H+6*0=6*12+12*1+6*16=180

O*6=16*6=96Calculate molecular weight 6*C+12*H+6*0=6*12+12*1+6*16=180SO % Of O=(96/180)*100=53.3% present

in glucose

glucoseThank you

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