Question

calculate the change in kinetic energy if it's velocity reduced by one third of the initial velocity?​

Answer 1

Answer:

Change is (5/9)K₁     ;  decreased by (5/9) of the initial

Explanation:   General method:

As we know,   K ∝ v² ;  

          let K₁ = xv² ,    where x is a constant

If v is reduced by 1/3,  new velocity is

       ⇒ v - v/3  

       ⇒ 2v/3

Therefore,    K₂ = x(2v/3)² = (4/9)xv²

                     K₂ = (4/9) K₁

Hence, the change in K is

  ΔK = K₂ - K₁

        = (4/9)K₁ - K₁

        = - (5/9)K₁

This means,  K is decreased by 5/9 .

Answer 2

$\sf\tt\large{\green {\underline {\underline{⚘\;Question:}}}}$

• Calculate the change in kinetic energy if its velocity reduced to one third of the initial velocity.

$\sf\tt\large{\red {\underline {\underline{⚘\;Answer:}}}}$

$\sf\tt\large{\blue {\underline {\underline{⚘\;The \;correct \;Answer \;is \;the \;change \;in \;kinetic \;energy \;is \;(8/9) \;of \;its \;initial \;velocity:}}}}$

$\sf\tt\large{\green {\underline {\underline{⚘\;Solution:}}}}$

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$\sf\tt\large{\red {\underline {\underline{⚘\;Thank \;you:}}}}$