Calculate the electronegativity of chlorine if the electronegativity of fluorine is 4.0.Given excess bond energy of Cl - F.bond is 14.68 kcal mol ^(-1)
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Δ=(BE)Cl−F−√(BE)Cl−Cl(BE)F−F
=61−√58×38
=61−46.95
=14.05
kcal
(EN)Cl=(EN)F−0.208√Δ
=4.0−0.208√14.05
=4.0−0.78
=3.22eV
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