calculate the equivalent resistance between points A and B in the following network of the resistors.
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Answered by
11
1/R=1/6+1/6+1/6
= (1+1+1)/6
=3/6
1/R=1/2
R =2 ohm
= (1+1+1)/6
=3/6
1/R=1/2
R =2 ohm
singhanimagaur103:
thank you
Answered by
5
It is in series combination so:-
=>R(e)=R1+R2+R3.....
=>R(e)=6+6+6
=>R(e)=18 ohm
Hope it'll Help You.....
Have a great day.
=>R(e)=R1+R2+R3.....
=>R(e)=6+6+6
=>R(e)=18 ohm
Hope it'll Help You.....
Have a great day.
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