calculate the mass of carbon monoxide having same number of oxygen atoms as present in 88 grams of CO2.
please friends I need it urgently !
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Answered by
235
no of oxygen atoms in CO2 = 2× 88/44 × Avogadro's constant
no of oxygen atoms = weight of CO/28 × Avogadro's constant
no of oxygen atoms in CO2 = no of oxygen atoms in CO
2× 88/44 = weight of CO/28
weight of CO = 112 g
no of oxygen atoms = weight of CO/28 × Avogadro's constant
no of oxygen atoms in CO2 = no of oxygen atoms in CO
2× 88/44 = weight of CO/28
weight of CO = 112 g
abhi178:
now answer iz correct
but I had talked about carbon monoxide
yes carbon monoxide CO
formula, of carbon monoxide = CO
hmm
thanks very much brother
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46
Hi there..
Hope it helps..
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