Question

calculate the molality of 20% by mass rotation of k2 co3 ​

Answer 1

Answer:

1.75

Explanation:

formula:

mass solute /mass solution×100

so,

0.2=20/100

20 solute

80 solvent

moles =20/138

moles =0.14

molality = moles / solvent (kg)

= 0.14/0.08

ans=1.75